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Dez Bryant Named NFC Offensive Player Of The Week After 3-TD Night

IRVING, Texas – Dez Bryant was named NFC Offensive Player of the Week on Wednesday morning – an unsurprising development, given his dominant display Sunday night in Philadelphia.

Bryant turned in one of the best performances of his five-year career in the 38-27 win against the Eagles. He hauled in six catches for 114 yards and three touchdowns – the last of which put the Cowboys up by two possessions in the fourth quarter.

It was the first time Bryant has notched three touchdowns in a single game, and that output pushed him to 13 touchdowns for the season – tying his career high for a single season and making him the NFL's leader in receiving touchdowns.

Sunday night was also the fourth time Bryant has gone for 100 yards or more this season, and the 14th time in his career.

As he nears the end of his rookie contract, Bryant has 79 catches for 1,148 yards and those 13 touchdowns. He's on pace to finish with 90 catches for 1,312 yards, and if he does, he'll have put together three consecutive seasons with 90 or more catches for 1,200-plus yards. He has already achieved double-digit touchdowns for his third straight season.

Elsewhere in the NFC, Lions safety Glover Quin notched three tackles and a pick-six to earn Defensive Player of the Week, while Cardinals kicker Chandler Catanzaro kicked four field goals, thereby providing all of Arizona's points, to win Special Teams Player of the Week.

Bengals running back Jeremy Hill won AFC Offensive Player of the Week honors, while Denver corner Aqib Talib and Kansas City punt returner De'anthony Thomas nabbed the defensive and special teams award, respectively.

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